What is wrong with the following code

#include<iostream>
using namespace std;
struct S
{
	int i;
	int *p;
};

int main()
{
	//S s; // 结构体没有初始化，怎么会有地址的分配改写如下
	//s.i = 1;
	//int q = 2;
	//s.p = &q;
	//cout << "&s.i= " << &s.i << endl;
	S s;
	int *p = &s.i;  // p 指针指向s.i，相当于int *p;p = &s.i;
	cout << "p= " << p << endl;
	p[0] = 4;  // 相当于赋值给s.i;
	p[1] = 3;  // 相当于赋值给S.p,即是s.p里储存的值为3，而不是某个变量的地址
	cout << "s.i= " << s.i << endl;
	cout << "s.p= " << s.p << endl;
	cout << "&s.i= " << &s.i << endl;
	cout << "&s.p= " << &s.p << endl;
	cout << "p[0]= " << p[0] << endl;
	cout << "p[1]= " << p[1] << endl;
	s.p = p;  // 即是把00000003的值在赋给s.p，那么s.p指向的内存块的地址是00000003，	s.p[1] = 1;//s.p[1]指向的地址是00000004，直接把1赋给一个不知道的内存块会出错
	s.p[2] = 2;
	return 0;
}

输出的结果如下：
         cout << "s.i= " << s.i << endl;    4
cout << "s.p= " << s.p << endl;    00000003
cout << "&s.i= " << &s.i << endl;  0012FF5C
cout << "&s.p= " << &s.p << endl;  0012FF60
cout << "p[0]= " << p[0] << endl;  4
cout << "p[1]= " << p[1] << endl;  3
由以上输出可以看出：
               1.int *p = &s.i;是把s.i的地址赋给指针P，即：p=&s.i
             2.p[0]代表s.i;p[1]=s.p;
             3.p[1]=3;即是s.p指针值为3，指向变量的地址为3